9x4y12x8y32 9x12x4y8y323x12y32 (answer) hope it helpspls follow meYou can check out similar questions with solutions below Please tell fast Factorise 4x ^2 9y ^2 6x 9y solve the equation please factorise 4x (square) 9y (square) 16y (spuare) factorise 4xFactrorise4x29y216z212xy−24xyz−16zx 4x29y216z212xy−24xyz−16zxUsing identity abc2=a2b2c22ab2bc2ca4x29y216z212xy−24yz−16xz=2x23y2−4z22×2x× Grade Factrorise4x29y216z212xy−24xyz−16zx 4x29y216z212
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Factorise 2x+y)^2-9(x+y)-5-On the other hand, 2x 2 – 162 = 2(x 2 – 81), and x 2 – 81 is a quadratic When you see that you have a twoterm nonlinear polynomial, check to see if it fits any of the formulas In this case, you've got a difference of squares, so apply that formula 2x 2 – 162 = 2(x 2 – 81) = 2(x – 9)(x 9) Warning Always remember that, in cases like 2x 2 162, all you can do is factor outDonc dans x P1 y x P2 y 2 x 2 y P2 xy P1 on entend TOUS les monômes de la forme x Pk y k, k allant de 1 à P1 Voila un dénomination un peu plus complexe et vraiment mathématique
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1215 days 11 hours 22 minutes ago Pranav👍 Correct answer to the question B) Factorise fully 8x2 6x eeduanswerscomJust as y = mx b is a useful format for graphing linear functions, y = a(x h)^2 k is a useful format for graphing quadratic functions We will explore its uses and learn how to convert any
Get a free home demo of LearnNext Available for CBSE, ICSE and State Board syllabus Call our LearnNext Expert on 1800 419 1234 (tollfree) OR submit details below for a call back4 Alternative versions feel free to create and share an alternate version that worked well for your class following the guidance hereThe Auxiliary Equation is m^23m2=0 m=1,2 ⸫ x=Ae^tBe^2t , A , B are constants Now from given condition, x(0)=0 , thus AB=0 Also x'=Ae^t2Be^2t From x' (0)=0 , B=0 From the above A=B=0 Hence x=0 is the solution
But this system, since Y appears only as a squared term, can be solved in other ways We can solve for y^2 instead of y and substitute for y^2 We can use the Elimination (aka Linear Combination or Addition) Method I will use the first one of these Solve the second equation for y^2 Subtract (x1)^2 from both sides givingAlgebra Factor 9x^224xy16y^2 9x2 − 24xy 16y2 9 x 2 24 x y 16 y 2 Rewrite 9x2 9 x 2 as (3x)2 ( 3 x) 2 (3x)2 − 24xy16y2 ( 3 x) 2 24 x y 16 y 2 Rewrite 16y2 16 y 2 as (4y)2 ( 4 y) 2 (3x)2 − 24xy(4y)2 ( 3 x) 2 24 x y ( 4 y) 2 Check that the middle term is two times the product of the numbers being squared in the first 2 Activity 2 3 Downloadable version Applying Rules of Indices VT;
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Band students are tested on, and required to pass, a certain number of scales during the year As of today, Isaac has passed 9 scales, whereas his fri end Audrey has passed 14 of them Going forward, Isaac has committed to passing 3 scales per week, and Audrey has committed to passing 2 per week2 recall that we can factorise this and make up for any inaccuracies in our factorising for example, x^26x=(x3)^29 (the minus 9 compensates for the unwanted constant term coming out of this equation) Doing this with both x and y yeilds (x3)^29(y2)^24=233This looks a lot nicer!Procedimiento Identificar los términos de un o más trinomios cuadrados perfectos y agruparlos Factorizar el trinomio o trinomios cuadrados perfectos Con el resultado del trinomio y el o los otros términos de la expresión formar una diferencia de cuadrados Factorizar la diferencia de cuadrados Simplificar para llegar a la solución final
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X(x^2 9) = 0 Factorise by taking out a common factor then use the difference of two squares and solve to find the values of Equation x x(x 3)(x 3) = 0 x = 0, x = 3, x = 3 These are the three x coordinates of where the curve and straight line meetZ = 1/ (X Y) Therefore the given equation becomes X^2 Y^2 1/ (X^2 Y^2) = X Y 1/ (X Y) Solving this equation for Y we have Y = 1/4 {1 Sqrt (A) Sqrt 2 B 2 Sqrt (A)} where A = 1 8/X 4 X 4 X^2 and B = 1 4/X 2 X 2 X^2 If we want real solutions, the only solution for Y Polynomial to factorise $$ 2x^2 y^2 3y = 0 $$ This is what I did but couldn't reach the final factors $$\ 2x^2 2 y^2 3y 2 = 0 $$ $$\ 2(x1)(x1)
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x(2x4) ou 2x(x2) ou alors elle sont juste toute les deux Posté par Eipihc re factorisation à 1501 eh bien dans les deux cas tu as factorisé mais selon moi la meilleur est la deuxième puisque tu as factorisé au "maximum" Posté parExpressions of the form ax or ax, where a > 1, are called exponential functions The graph of an exponential function has one of these shapes y ax where a > 1 or y bx where O < b < I exponential growth y ax where a > 1 or y bx where O < b < I exponential decay Exponential graphs intersect the yaxis at (O, I) because ao I for all values of aThis question has not been answered yet!
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4x^29y^216z^212xy24yz16zx If the lines represented by 4x^(2)12xy9y^(2)6x9y=1 are 2 tangents to a circle then its area isCORRECTION Answer b is incorrect the correct answer is 4a^2 12a9Thanks Aditi JainAlgebraic Identities https//wwwyoutubecom/watch?v=HQWggFJVmKQ&list=PLWhen x = 3, the left hand side of the equation equals 2This is not equal to the right hand side of the equation, 0x = 3 does not solve the equationx = 1 and x = 2 solve the quadratic equation x 2 − 3x 2 = 0A quadratic equation will always have 2 values of x that solve the equation There are always 2 roots How to Solve Quadratic Equations There are 3 ways to solve quadratic equations
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EAch term can be factored by differemce of squares xy(x^2y^2) yz(y^2z^2) zx(z^2x^2) =xy(xy)(xy) yz(yz)(yz) zx(zx)(zx) The only other option would be to multiply out the brackets and try a different grouping, but I don not think itF (x)=x 3 3x 2 9x27 determine the zeros, their multiplicity, and whether the graph will touch or cross the xaxis at each zero Then, determine the end behavior of the function and sketch a graph of the function check_circle Get a free home demo of LearnNext Available for CBSE, ICSE and State Board syllabus Call our LearnNext Expert on 1800 419 1234 (tollfree) OR submit details below for a
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X2y= 210 x 2 y = 2 10 The function y =x3 y = x 3 is always increasing, so we don't lose any solutions by doing this Let's try to systematically list the pairs of positive integers ( x x, y y) that would satisfy this equation The value x = 1 x = 1 does notFactorise 18x3y3−27x2y336x3y2 9x2y22xy−3y4x 9x2y22xy3y4x 9x2y22xy−3y−4x 9x2y22xy3y−4x 18x3y3−27x2y336x3y218x3y3=2×3×3×x×x×x×y×y×y27x2y3=3×3×3×x×x×y×y Grade Factorise 18x3y3−27x2y336x3y2 9x2y22xy−3y4x 9x2y22xyIn Click here to see ALL problems on Quadratic Equations Question 097 Factor completely x^2 3x 28 Found 2 solutions by josmiceli, bucky Answer by josmiceli () ( Show Source ) You can put this solution on YOUR website!
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Factor 64(x y) 3 27y 3 We have another costumed crusader here This time, they've disguised their variables to look more complicated than they actually are It's still a sum of two cubes, though Rewrite as 4(x y) 3 (3y) 3 That makes it more obvious Our terms are 4(x y) and 3y By the change of base formula, $\log_4{x^22x1}$ is equal to $\frac{\log_2{x^22x1}}{\log_2{4}}$, or $\frac{1}{2} \log_2{x^22x1}$ Since both sides are in the same base, we can directly solve the inequalityAfter this, the expression is much simpler, all that is required is to find two numbers that add to make (7) and multiply to make (12) In this case the numbers are (3) and (4) leading to (2(X^2 4X 3X 12)) Writing down this step may be confusing so it can often be skipped The final step is to factorise, the answer is (2(X 4)(X 3))
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VarunRawat, Meritnation Expert added an answer, on 26/8/14 VarunRawat answered this x 3 8 y 3 27 z 3 18 x y z = x 3 2 y 3 3 z 3 3 x 2 y 3 z = x 2 y 3 z x 2 2 y 2 3 z 2 x 2 y 2 y 3 z 3 z x = x 2 y 3 z x 2 4 y 2 9 z 2 2 x y 6 y z 3 z xY = x2 6x 9 y = (x3)2 9 9 y = (x3)2 18 y 18 = (x3)2 y 18 ≥ 0 y ≥ 18 Find the minimum or maximum value for y Sep 61955 Completing the Square to Solve Problems LO all pupils can use their completing the square knowledge to •find the range of values for y •find the vertex and the equation of the line of symmetry Factorise 9(xy)^216(p2q)^2 2 See answers harsh0612 harsh0612 Here's the answer hope it helps you
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एक असमान अनुप्रस्थ काट क्षेत्रफल वाली नली से क्षैतिज दिशा में पानी बह रहा है। यदि 002 अनुप्रस्थ काट क्षेत्रफल वाले बिन्दु पर दाब तथा द्रव का वेग 2 m/s है तो उस बिन्दु पर दाब क्या होगा जहां We are given 9x2 24xy 16y2 We want to obtain an expression of the form (ax by)(cx dy) where a,b,c,d are integers (not necessarily unique from each other) Expanding this form we get acx2 adxy bcxy bdy2 acx2 (ab cd)xy bdy2 Find an answer to your question Plot on graph h(x)=(x1)^24 Plot the xintercept(s), yintercept, vertex, and axis of symmetry of the function Brainly User Brainly User
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Class Notes Class VIII Topic Ch14, FACTORISATION Subject MATHEMATICS EXERCISE – 142 Q3 Factorise the expressions Solution (i) ax👉Learn how to factor quadratics A quadratic is an algebraic expression having two as the highest power of its variable(s) To factor an algebraic expressioSolutionShow Solution 4y 2 = (2y) 2, 9 = 3 2 and 12y = 2 × 3 × (2y) Therefore, 4y 2 – 12y 9 = (2y) 2 – 2 × 3 × (2y) (3) 2 = ( 2y – 3) 2 (required factorisation) Concept Factorisation
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The thing to notice is that certain factors of 28 are 4 and 7Factorise x^323x^2 142x1 Factorise y^2 5y6 Factorise 25x^2/4 y^2/9 Find the remainder on dividing p(x) =x^3 1 by x1 Tweet Description test your skills on algabra Discussion GanErdene i got 054 that score is not that bad right?Inequalities using Arithmetic Mean Geometric Mean Arithmetic Mean of a and b is always greater than or equal to the Geometric Mean of a and b, for all positive real numbers with with equality if and only if a = b This is also called AMGM (Arithmetic Mean Geometric Mean) inequality a b 2 ≥ √ab or a b ≥ 2√ab
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2et x 2=(9)p 9 2(3) = 93 6 = 1 D'après le corolaire on en déduit que 3x29x6= 3(x1)(x2) ce qui peut se véri er en développant l'expression de droite 2Déterminons toute les solutions de l'équation x3 x= 0 Nous commençons par observer qu'il est possible de factoriser par xpour avoir x3x= x(x21) actorisonsF le polynôme de Factorise(xyz)^3 (xyz)^3 8x^3 Math Fully factorise 16x^36 1 math Factorise 25a^235a12 Maths Methods Factorise 5x^2 8x 3 You can view more similar questions or ask a new questionFactor y^210y9 y2 − 10y 9 y 2 10 y 9 Consider the form x2 bxc x 2 b x c Find a pair of integers whose product is c c and whose sum is b b In this case, whose product is 9 9 and whose sum is −10 10 −9,−1 9, 1 Write the factored form using these integers (y−9)(y−1) ( y 9) ( y 1)
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Taking the constant terms all to one side we get (x3)^2(y2)^2=362 9 peut être factorisé en x 3 et x 3 Ce n'est pas une procédure couramment utilisée dans la vie de tous les jours Une partie de la raison est que les exemples donnés dans la classe d'algèbre sont si simples et que les équations ne prennent pas une forme aussi simple dans les classes de niveau supérieur1 of 2 SC Version 10 Quadratic card sort Place the cards below on the grid on page 2, aiming for at least one in each cell If this is not possible, explain why y x 2 2x 4y x 2 5x 4 y 2x 2 5x 3 y 2 x 4 y 2x 2 7x 3 y 4 3 x y x 2 5x 2 y 6x 2 9 y x 2 3x 1 y 2 10x 9 y x
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